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	<title>Comments on: What Affect Would Several Miles Of Ocean Have On A Body/bones When It Comes To Radiocarbon Dating?</title>
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	<link>http://chooseafriend.com/19002/what-affect-would-several-miles-of-ocean-have-on-a-bodybones-when-it-comes-to-radiocarbon-dating/</link>
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		<title>By: BARNEY_K</title>
		<link>http://chooseafriend.com/19002/what-affect-would-several-miles-of-ocean-have-on-a-bodybones-when-it-comes-to-radiocarbon-dating/comment-page-1/#comment-7845</link>
		<dc:creator>BARNEY_K</dc:creator>
		<pubDate>Fri, 11 Dec 2009 01:28:45 +0000</pubDate>
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		<description>yes it would</description>
		<content:encoded><![CDATA[<p>yes it would</p>
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	<item>
		<title>By: darkrevn</title>
		<link>http://chooseafriend.com/19002/what-affect-would-several-miles-of-ocean-have-on-a-bodybones-when-it-comes-to-radiocarbon-dating/comment-page-1/#comment-7844</link>
		<dc:creator>darkrevn</dc:creator>
		<pubDate>Thu, 10 Dec 2009 23:42:13 +0000</pubDate>
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		<description>No.
Radiocarbon dating uses something called &#039;closure temperatures&#039;.  This temperature is the warmest a rock can be and still allow for the radioactive byproduct to migrate out of the crystal.  (Lowest temp is for Hydrogen scattering and that is 100C Oxygen and Carbon are higher; so in a fault, hydrothermal deposit, or volcano you would have some loss of byproducts (but knowing the geology could give you another stratigraphic date.))
Radioactivity has a half-life; that means half the material will be gone after that amount of time.  But to get it all gone is a very long time.  However the byproduct is still there, and the rock is too cool to allow the newly formed element to migrate out.
So in a lab the rock is pulverized and sanadine; mica; zircons etc are pulled out and then dissolved with Tetra-hydrofluride (or another fun Fluorine compound) and the resulting elements are sent on their merry way through a Gas Spectrometer or Gas Chromatography.  As the elements travel they split into like elements and the resultant peaks can be calculated to give the total.  Radioactive isotope plus byproduct gives original amount of radioactive element at time of crystal formation or closure temperature reached.
Know the half life time, figure out the ratio of Radioactive isotope to daughter byproduct and you get your date.</description>
		<content:encoded><![CDATA[<p>No.<br />
Radiocarbon dating uses something called &#8216;closure temperatures&#8217;.  This temperature is the warmest a rock can be and still allow for the radioactive byproduct to migrate out of the crystal.  (Lowest temp is for Hydrogen scattering and that is 100C Oxygen and Carbon are higher; so in a fault, hydrothermal deposit, or volcano you would have some loss of byproducts (but knowing the geology could give you another stratigraphic date.))<br />
Radioactivity has a half-life; that means half the material will be gone after that amount of time.  But to get it all gone is a very long time.  However the byproduct is still there, and the rock is too cool to allow the newly formed element to migrate out.<br />
So in a lab the rock is pulverized and sanadine; mica; zircons etc are pulled out and then dissolved with Tetra-hydrofluride (or another fun Fluorine compound) and the resulting elements are sent on their merry way through a Gas Spectrometer or Gas Chromatography.  As the elements travel they split into like elements and the resultant peaks can be calculated to give the total.  Radioactive isotope plus byproduct gives original amount of radioactive element at time of crystal formation or closure temperature reached.<br />
Know the half life time, figure out the ratio of Radioactive isotope to daughter byproduct and you get your date.</p>
]]></content:encoded>
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	<item>
		<title>By: WP Autoblog Software</title>
		<link>http://chooseafriend.com/19002/what-affect-would-several-miles-of-ocean-have-on-a-bodybones-when-it-comes-to-radiocarbon-dating/comment-page-1/#comment-7843</link>
		<dc:creator>WP Autoblog Software</dc:creator>
		<pubDate>Thu, 10 Dec 2009 17:54:01 +0000</pubDate>
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		<description>None. It might be different for &quot;EFFECT,&quot; though. Buy a dictionary.</description>
		<content:encoded><![CDATA[<p>None. It might be different for &#8220;EFFECT,&#8221; though. Buy a dictionary.</p>
]]></content:encoded>
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		<title>By: Best Smartphone Software</title>
		<link>http://chooseafriend.com/19002/what-affect-would-several-miles-of-ocean-have-on-a-bodybones-when-it-comes-to-radiocarbon-dating/comment-page-1/#comment-7842</link>
		<dc:creator>Best Smartphone Software</dc:creator>
		<pubDate>Thu, 10 Dec 2009 13:47:10 +0000</pubDate>
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		<description>No it would not - I&#039;m an earth scientist....</description>
		<content:encoded><![CDATA[<p>No it would not &#8211; I&#8217;m an earth scientist&#8230;.</p>
]]></content:encoded>
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		<title>By: Nishaant Kapoor</title>
		<link>http://chooseafriend.com/19002/what-affect-would-several-miles-of-ocean-have-on-a-bodybones-when-it-comes-to-radiocarbon-dating/comment-page-1/#comment-7841</link>
		<dc:creator>Nishaant Kapoor</dc:creator>
		<pubDate>Thu, 10 Dec 2009 12:19:39 +0000</pubDate>
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		<description>Yeah, you&#039;re right, but most of these factors ARE taken into consideration, eg. the depth from which the fossil has been extracted. But I&#039;m pretty sure that the concentration of 02 in the past has never been taken into account. I think that there must not have been a very large difference, must have been more or less the same. That is why, the figure given is approximately that much and is not an exact one.
Hope that helps.</description>
		<content:encoded><![CDATA[<p>Yeah, you&#8217;re right, but most of these factors ARE taken into consideration, eg. the depth from which the fossil has been extracted. But I&#8217;m pretty sure that the concentration of 02 in the past has never been taken into account. I think that there must not have been a very large difference, must have been more or less the same. That is why, the figure given is approximately that much and is not an exact one.<br />
Hope that helps.</p>
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